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 If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –> Y be the correspondence which assigns each element in X the value equal to its square, then the domain, co-domain and range of f is
  • a)
    Domain = {1, 2, …, 20}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, 4}
  • b)
    Domain = {1, 4, 9, 16}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, …, 16}
  • c)
    Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 20}
  • d)
    Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 16}
Correct answer is option 'B'. Can you explain this answer?
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If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –>...
The correct option is B
Since the function is defined from 
XY.So the domain will be the set X which is {1,2,3,4}. Codomain is  what may possibly come out of a function. So codomain is the whole set Y which is {1,2,3,...,20}. Range is The range is the set of possible output values which will be the values in the set of Y which have a pre-image. That is, the value of squares. So the range is {1,4,,9,16}. 
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If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –>...
Correct answer is c because the function is from x to y not from y to x.
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If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –> Y be the correspondence which assigns each element in X the value equal to its square, then the domain, co-domain and range of f isa)Domain = {1, 2, …, 20}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, 4}b)Domain = {1, 4, 9, 16}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, …, 16}c)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 20}d)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 16}Correct answer is option 'B'. Can you explain this answer?
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If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –> Y be the correspondence which assigns each element in X the value equal to its square, then the domain, co-domain and range of f isa)Domain = {1, 2, …, 20}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, 4}b)Domain = {1, 4, 9, 16}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, …, 16}c)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 20}d)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 16}Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –> Y be the correspondence which assigns each element in X the value equal to its square, then the domain, co-domain and range of f isa)Domain = {1, 2, …, 20}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, 4}b)Domain = {1, 4, 9, 16}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, …, 16}c)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 20}d)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 16}Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If X = {1, 2, 3, 4}, Y = {1, 2, 3,…., 20}, and f: X –> Y be the correspondence which assigns each element in X the value equal to its square, then the domain, co-domain and range of f isa)Domain = {1, 2, …, 20}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, 4}b)Domain = {1, 4, 9, 16}, Range = {1, 2, 3, 4}, Co domain = {1, 2, 3, …, 16}c)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 20}d)Domain = {1, 2, 3, 4}, Range = {1, 4, 9, 16}, Co domain = {1, 2, 3, …, 16}Correct answer is option 'B'. Can you explain this answer?.
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